cs601 assignment 2 fall 2017
 What is its solution?......................
Question No.1:                                                                                                                  12 Marks
Consider a noisy channel, which has a bandwidth of 400KHz and theoretical channel capacity of 4.01Mbps (according to Shannon Capacity formula).
a.     Calculate the Signal Power received at the receiver end if the Noise Power is .001 Watt.
b.     Also calculate the signal to noise ratio of the channel in dB (SNRdB).
      Provide your answer in correct units with full calculation.

Answers with proper Units

Question No. 2:                                                                                                                  8 Marks
A signal of power 6 mW is transmitted through a cable. If the signal encounters a loss of 6db due to impairments of the transmission medium. Calculate the power received at the receiver end.
                                     Relative signal strength before and after power loss with unit
Note: Give your solution with all relevant calculations in given tables.
Wish You All The Best
These are realated to lecture no 28 in your handouts
Question no 1
given data S=? N=0.001watt B=400KHZ C=4.01Mbps
we know that
C=B log2(1+S/N) in bps
is ma values put kar ky answer nikal lo.
Question no 2:
p1=6mW dB=6db p2=?
we know that
dB=10 log10(p2/p1) put all values and get result
now relative streangth before is (Amplified)and after is also (Amplified)
Good luck!...............
Dear As its Loss of power in Question 2. is't it attenuation. and attenuation always measured in -ve. so it would be -6db while calculating.

How to calculate power of signal in question 1? only Bandwidth and noise power is given. Shannon capacity formula is for calculating channel capacity.

Please Help
yes you are right in Question no 2.its loss of energy -6db.
Question no 1:
C=B log2(1+S/N) in bps
4.01 Mbps = 400KHZ log2(1+S/0.001) in bps
next kiya step ha i have no idea please help me
Question no 2:
dB=10 log10 (p2/p1)
-6db=10 log10 (p2/6mW)
is question ka bh next step nahe pata you have any idea please help me........

hum (log) ky step ko kasy solve kary gy in both Questions..........
you have any idea please please help me.........
Here is the complete solution guys: CS601 Assignment 2 Solution Fall 2017
i need phy101 assignment soltuion
(01-15-2018, 12:00 PM)Muskan Khan Wrote: i need phy101 assignment soltuion

Kindly post assignment questions in a new topic in the appropriate forum to get help.
Here is your solution for now Phy101 Assignment 3 Solution Fall 2017

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