07-11-2017, 11:09 AM
CS601 Data Communication
Assignment 3 - Spring 2017
Solution:
Question No. 1
Imagine a signal (P1) travels through an amplifier and its power is increased 20 times. This means that P2 (the amplified signal) =20P1.
You are required to calculate the amplification (gain of power) by writing all necessary calculations and formula.
Answer:
How to calculate signal amplification
Formula for Signal Amplification: 10 log (P2/P1)
Putting the above values,
= 10 log (20P1/P1)
= 10 log (20)
= 13 dB.
Question No. 2
Suppose that S/N i.e. signal to noise ratio = 34dB and bandwidth of the channel is 2 kHz. You are required to calculate the theoretical channel capacity in bps by writing all necessary calculations and formula.
Answer:
How to calculate Channel Capacity
Formula for Channel Capacity = B log base 2 (1 + S/N ) in bps
Here,
B = Bandwidth of the channel = 2 kHz = 2000 Hz
S/N = Signal to Noise ratio = 34 dB = 2511
Putting the values in the formula:
= 2000 log base 2 ( 1 + 2511)
= 22,589 bps
Comment below for any questions.
Assignment 3 - Spring 2017
Solution:
Question No. 1
Imagine a signal (P1) travels through an amplifier and its power is increased 20 times. This means that P2 (the amplified signal) =20P1.
You are required to calculate the amplification (gain of power) by writing all necessary calculations and formula.
Answer:
How to calculate signal amplification
Formula for Signal Amplification: 10 log (P2/P1)
Putting the above values,
= 10 log (20P1/P1)
= 10 log (20)
= 13 dB.
Question No. 2
Suppose that S/N i.e. signal to noise ratio = 34dB and bandwidth of the channel is 2 kHz. You are required to calculate the theoretical channel capacity in bps by writing all necessary calculations and formula.
Answer:
How to calculate Channel Capacity
Formula for Channel Capacity = B log base 2 (1 + S/N ) in bps
Here,
B = Bandwidth of the channel = 2 kHz = 2000 Hz
S/N = Signal to Noise ratio = 34 dB = 2511
Putting the values in the formula:
= 2000 log base 2 ( 1 + 2511)
= 22,589 bps
Comment below for any questions.